
This function can generate a Box-Behnken design in 3 to 7 factors, and optionally will block it orthogonally if there are 4 or 5 factors. It can also randomize the design.
bbd(k, n0 = 4, block = (k == 4 | k == 5), randomize = TRUE, coding)
A coded.data
object with the generated design and the additional valiables run.order
and std.order
. The blocking variable, if present, will be a factor
; all other variables will be numeric.
A formula, or an integer giving the number of variables. If the formula has a left-hand side, the variables named there are appended to the design and initialized to NA
.
Number of center points in each block.
Logical value specifying whether or not to block the design; or a character string (taken as TRUE
) giving the desired name for the blocking factor.
Only BBDs with 4 or 5 factors can be blocked. A 4-factor BBD has three orthogonal blocks, and a 5-factor BBD has two.
Logical value determining whether or not to randomize the design. If block
is TRUE
, each block is randomized separately.
Optional list of formulas. If this is provided, it overrides the default coding formulas.
Russell V. Lenth
Box-Behnken designs (BBDs) are useful designs for fitting second-order response-surface models. They use only three levels of each factor (compared with 5 for central-composite designs) and sometimes fewer runs are required than a CCD. This function uses an internal table of BBDs; it only works for 3 to 7 factors.
If k
is specified as a formula, the names in the formula determine the names of the factors in the generated design. Otherwise, the names will be x1, x2, ...
. If coding
is not specified, default codings are created in the form x ~ x.as.is.
Lenth RV (2009) ``Response-Surface Methods in R, Using rsm'', Journal of Statistical Software, 32(7), 1--17. tools:::Rd_expr_doi("10.18637/jss.v032.i07")
Myers, RH, Montgomery, DC, and Anderson-Cook, CM (2009) Response Surface Methodology (3rd ed.), Wiley.
ccd
, coded.data
library(rsm)
### Simple 3-factor case, not randomized so structure is evident
bbd(3, randomize=FALSE)
### 5-factor BBD, divided between two plants
bbd(y1 + y2 ~ A + B + C + D + E, n0 = 5, block = "Plant")
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