Remove/replace/extract percentages from a string.
rm_percent(text.var, trim = !extract, clean = TRUE,
pattern = "@rm_percent", replacement = "", extract = FALSE,
dictionary = getOption("regex.library"), ...)ex_percent(text.var, trim = !extract, clean = TRUE,
pattern = "@rm_percent", replacement = "", extract = TRUE,
dictionary = getOption("regex.library"), ...)
The text variable.
logical. If TRUE removes leading and trailing white
spaces.
trim logical. If TRUE extra white spaces and escaped
character will be removed.
A character string containing a regular expression (or
character string for fixed = TRUE) to be matched in the given
character vector. Default, @rm_percent uses the
rm_percent regex from the regular expression dictionary from
the dictionary argument.
Replacement for matched pattern.
logical. If TRUE the percentages are extracted into a
list of vectors.
A dictionary of canned regular expressions to search within
if pattern begins with "@rm_".
Other arguments passed to gsub.
Returns a character string with percentages removed.
Other rm_ functions: rm_abbreviation,
rm_between, rm_bracket,
rm_caps_phrase, rm_caps,
rm_citation_tex, rm_citation,
rm_city_state_zip,
rm_city_state, rm_date,
rm_default, rm_dollar,
rm_email, rm_emoticon,
rm_endmark, rm_hash,
rm_nchar_words, rm_non_ascii,
rm_non_words, rm_number,
rm_phone, rm_postal_code,
rm_repeated_characters,
rm_repeated_phrases,
rm_repeated_words, rm_tag,
rm_time, rm_title_name,
rm_url, rm_white,
rm_zip
# NOT RUN {
x <- c("There is $5.50 for me.", "that's 45.6% of the pizza",
"14% is $26 or $25.99")
rm_percent(x)
ex_percent(x)
# }
Run the code above in your browser using DataLab