
Extract or replace substrings in a character vector.
substr(x, start, stop)
substring(text, first, last = 1000000L)
substr(x, start, stop) <- value
substring(text, first, last = 1000000L) <- value
a character vector.
integer. The first element to be replaced.
integer. The last element to be replaced.
a character vector, recycled if necessary.
For substr
, a character vector of the same length and with the
same attributes as x
(after possible coercion).
For substring
, a character vector of length the longest of the
arguments. This will have names taken from x
(if it has any
after coercion, repeated as needed), and other attributes copied from
x
if it is the longest of the arguments).
Elements of x
with a declared encoding (see
Encoding
) will be returned with the same encoding.
substring
is compatible with S, with first
and
last
instead of start
and stop
.
For vector arguments, it expands the arguments cyclically to the
length of the longest provided none are of zero length.
When extracting, if start
is larger than the string length then
""
is returned.
For the extraction functions, x
or text
will be
converted to a character vector by as.character
if it is not
already one.
For the replacement functions, if start
is larger than the
string length then no replacement is done. If the portion to be
replaced is longer than the replacement string, then only the
portion the length of the string is replaced.
If any argument is an NA
element, the corresponding element of
the answer is NA
.
Elements of the result will be have the encoding declared as that of
the current locale (see Encoding
) if the corresponding
input had a declared Latin-1 or UTF-8 encoding and the current locale
is either Latin-1 or UTF-8.
If an input element has declared "bytes"
encoding (see
Encoding
, the subsetting is done in units of bytes not
characters.
Becker, R. A., Chambers, J. M. and Wilks, A. R. (1988)
The New S Language.
Wadsworth & Brooks/Cole. (substring
.)
# NOT RUN {
substr("abcdef", 2, 4)
substring("abcdef", 1:6, 1:6)
## strsplit is more efficient ...
substr(rep("abcdef", 4), 1:4, 4:5)
x <- c("asfef", "qwerty", "yuiop[", "b", "stuff.blah.yech")
substr(x, 2, 5)
substring(x, 2, 4:6)
substring(x, 2) <- c("..", "+++")
x
# }
Run the code above in your browser using DataLab