# Replace NAs in a data frame
df <- tibble(x = c(1, 2, NA), y = c("a", NA, "b"))
df %>% replace_na(list(x = 0, y = "unknown"))
# Replace NAs in a vector
df %>% dplyr::mutate(x = replace_na(x, 0))
# OR
df$x %>% replace_na(0)
df$y %>% replace_na("unknown")
# Replace NULLs in a list: NULLs are the list-col equivalent of NAs
df_list <- tibble(z = list(1:5, NULL, 10:20))
df_list %>% replace_na(list(z = list(5)))
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