split_file(file, column, sep = NULL, outDir = file.path(dirname(file), "split"), prepend = "", dots = 1, skip = 0, verbose = TRUE)
''
, we guess the delimiter from the
first line.The focus is on efficient splitting of 'well-mannered' files, so if you have comments, quoted delimiters, cell entries that have paragraphs of unicode text, or other wacky things this is probably not the function for you.
extract_rows_from_file