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Matrix (version 1.4-1)

forceSymmetric: Force a Matrix to 'symmetricMatrix' Without Symmetry Checks

Description

Force a square matrix x to a symmetricMatrix, without a symmetry check as it would be applied for as(x, "symmetricMatrix").

Usage

forceSymmetric(x, uplo)

Value

a square matrix inheriting from class

symmetricMatrix.

Arguments

x

any square matrix (of numbers), either “"traditional"” (matrix) or inheriting from Matrix.

uplo

optional string, "U" or "L" indicating which “triangle” half of x should determine the result. The default is "U" unless x already has a uplo slot (i.e., when it is symmetricMatrix, or triangularMatrix), where the default will be x@uplo.

See Also

symmpart for the symmetric part of a matrix, or the coercions as(x, <symmetricMatrix class>).

Examples

Run this code
 ## Hilbert matrix
 i <- 1:6
 h6 <- 1/outer(i - 1L, i, "+")
 sd <- sqrt(diag(h6))
 hh <- t(h6/sd)/sd # theoretically symmetric
 isSymmetric(hh, tol=0) # FALSE; hence
 try( as(hh, "symmetricMatrix") ) # fails, but this works fine:
 H6 <- forceSymmetric(hh)

 ## result can be pretty surprising:
 (M <- Matrix(1:36, 6))
 forceSymmetric(M) # symmetric, hence very different in lower triangle
 (tm <- tril(M))
 forceSymmetric(tm)

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