This will calculate the distribution function of the piecewise uniform distribution
Usage
pwu(t=seq(0,1,by=0.1),u=c(0,5,0.5),ut=c(1,2))
Value
dist
distribution
Arguments
t
a vector of time points
u
piecewise constant density
ut
a strictly increasing sequence of time points defining the pieces. The first element must be strictly greater than zero. u and ut must have the same length.
Author
Xiaodong Luo
Details
Let \(f(t)=\sum_{j=1}^m u_j I(t_{j-1}<t\le t_j)\) be the density function, where \(u_1,\ldots,u_m\) are the corresponding elements of u and \(t_1,\ldots,t_{m}\) are the corresponding elements of ut and \(t_0=0\).
The distribution function $$F(t)=\sum_{j=1}^m u_j(t\wedge t_j-t\wedge t_{j-1}). $$
User must make sure that \(\sum_{j=1}^m u_j (t_j-t_{j-1})=1\) before using this function.