listDirectory: Gets the file names in the directory
Description
Gets the file names in the directory.
Contrary to list.files()
, this method guarantees to work
recursively. Moreover, when subdirectories are processed recursively,
directory names are also returned.Usage
## S3 method for class 'default':
listDirectory(pathname, pattern=NULL, recursive=FALSE, allNames=FALSE, fullNames=FALSE, ...)
Arguments
pathname
A pathname to be listed.
recursive
If TRUE
, subdirectories are recursively processed,
otherwise not. allNames
If TRUE
, also files starting with a period are returned. fullNames
If TRUE
, the full path names are returned. Value
- Returns a
vector
of file names.