shape
and scale
.
dinvweibull(x, shape, rate = 1, scale = 1/rate, log = FALSE)
pinvweibull(q, shape, rate = 1, scale = 1/rate, lower.tail = TRUE, log.p = FALSE)
qinvweibull(p, shape, rate = 1, scale = 1/rate, lower.tail = TRUE, log.p = FALSE)
rinvweibull(n, shape, rate = 1, scale = 1/rate)
minvweibull(order, shape, rate = 1, scale = 1/rate)
levinvweibull(limit, shape, rate = 1, scale = 1/rate, order = 1)
length(n) > 1
, the length is
taken to be the number required.TRUE
, probabilities/densities
$p$ are returned as $log(p)$.TRUE
(default), probabilities are
$P[X <= x]$,="" otherwise,="" $p[x=""> x]$.=>dinvweibull
gives the density,
pinvweibull
gives the distribution function,
qinvweibull
gives the quantile function,
rinvweibull
generates random deviates,
minvweibull
gives the $k$th raw moment, and
levinvweibull
gives the $k$th moment of the limited loss
variable.Invalid arguments will result in return value NaN
, with a warning.
shape
$= a$ and scale
$= s$ has density:
$$f(x) = \frac{\tau (\theta/x)^\tau e^{-(\theta/x)^\tau}}{x}$$
for $x > 0$, $a > 0$ and $s > 0$. The special case shape == 1
is an
Inverse Exponential distribution.
The $k$th raw moment of the random variable $X$ is $E[X^k]$ and the $k$th limited moment at some limit $d$ is $E[min(X, d)^k]$.
exp(dinvweibull(2, 3, 4, log = TRUE))
p <- (1:10)/10
pinvweibull(qinvweibull(p, 2, 3), 2, 3)
mlgompertz(-1, 3, 3)
levinvweibull(10, 2, 3, order = 1)
Run the code above in your browser using DataLab