data(sp5)
# EXAMPLE #1 -- resolving overlap
# 6 profiles in four sets, and 5,6,7 are missing
input <- lapply(list(c(1,3,4), c(2,2,3), NA, c(8,9,1)), function(idx) {
if(!all(is.na(idx)))
sp5[idx,]
})
output <- lunique(input)
# 6 profiles are in final SPC; 5,6,7 are missing
match(profile_id(pbindlist(output)), profile_id(sp5))
# EXAMPLE #2 -- exact duplicates
# deliberately duplicate an SPC
sp5_2 <- sp5
res <- lunique(list(sp5, sp5_2))
# the number of profiles in first element is equal to number in sp5
length(res[[1]]) == length(sp5)
# second list element contains NA b/c all uniques are in #1
res[[2]]
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