dendextend (version 1.17.1)

branches_attr_by_labels: Change col/lwd/lty of branches matching labels condition

Description

The user supplies a dend, labels, and type of condition (all/any), and TF_values And the function returns a dendrogram with branches col/lwd/lty accordingly

Usage

branches_attr_by_labels(
  dend,
  labels,
  TF_values = c(2, Inf),
  attr = c("col", "lwd", "lty"),
  type = c("all", "any"),
  ...
)

Value

A dendrogram with modified branches (col/lwd/lty).

Arguments

dend

a dendrogram dend

labels

a character vector of labels from the tree

TF_values

a two dimensional vector with the TF_values to use in case a branch fulfills the condition (TRUE) and in the case that it does not (FALSE). Defaults are 2/Inf for col, lwd and lty. (so it will insert the first value, and will not change all the FALSE cases)

attr

a character with one of the following values: col/lwd/lty

type

a character vector of either "all" or "any", indicating which of the branches should be painted: ones that all of their labels belong to the supplied labels, or also ones that even some of their labels are included in the labels vector.

...

ignored.

See Also

noded_with_condition, get_leaves_attr, nnodes, nleaves

Examples

if (FALSE) {

library(dendextend)

set.seed(23235)
ss <- sample(1:150, 10)

# Getting the dend dend
dend <- iris[ss, -5] %>%
  dist() %>%
  hclust() %>%
  as.dendrogram()
dend %>% plot()

dend %>%
  branches_attr_by_labels(c("123", "126", "23", "29")) %>%
  plot()
dend %>%
  branches_attr_by_labels(c("123", "126", "23", "29"), "all") %>%
  plot() # the same as above
dend %>%
  branches_attr_by_labels(c("123", "126", "23", "29"), "any") %>%
  plot()

dend %>%
  branches_attr_by_labels(
    c("123", "126", "23", "29"),
    "any", "col", c("blue", "red")
  ) %>%
  plot()
dend %>%
  branches_attr_by_labels(
    c("123", "126", "23", "29"),
    "any", "lwd", c(4, 1)
  ) %>%
  plot()
dend %>%
  branches_attr_by_labels(
    c("123", "126", "23", "29"),
    "any", "lty", c(2, 1)
  ) %>%
  plot()
}