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dendextend (version 1.18.1)

order.dendrogram<-: order.dendrogram<- assignment operator

Description

order.dendrogram<- assignment operator. This is useful in cases where some object is turned into a dendrogram but its leaves values (the order) are all mixed up.

Usage

order.dendrogram(object, ...) <- value

Value

dendrogram with updated order leaves values

Arguments

object

a variable name (possibly quoted) who's label are to be updated

...

parameters passed (not currently in use)

value

a value to be assigned to object's leaves value (their "order")

See Also

Examples

Run this code
################
# Example for using the assignment with dendrogram and hclust objects:
hc <- hclust(dist(USArrests[1:4, ]), "ave")
dend <- as.dendrogram(hc)

str(dend)
order.dendrogram(dend) # 4 3 1 2
order.dendrogram(dend) <- 1:4
order.dendrogram(dend) # 1 2 3 4
str(dend) # the structure is still fine.

# This function is very useful if we try playing with subtrees
# For example:
hc <- hclust(dist(USArrests[1:6, ]), "ave")
dend <- as.dendrogram(hc)
sub_dend <- dend[[1]]
order.dendrogram(sub_dend) # 4 6
# now using as.hclust(sub_dend) will cause trouble:
# labels(as.hclust(sub_dend)) # As of R 3.1.1-patched - this will produce an Error (as it should) :)
# let's fix it:

order.dendrogram(sub_dend) <- rank(order.dendrogram(sub_dend), ties.method = "first")
labels(as.hclust(sub_dend)) # We now have labels :)

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