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Calculates the lambda deformed exponential.
def.exp(x, lambda = 0, normalize = FALSE)
The function value of the lambda deformed exponential at x.
a numeric value.
deformation parameter. Default value: lambda = 0 (regular exponential).
lambda = 0
logical value to indicate normalization.
def.log.
def.log
def.exp(3) # Natural exponential of 3 def.exp(3,2) # Deformed by lambda = 2
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