doBy (version 4.6.21)

ls-means: Compute LS-means (aka population means or marginal means)

Description

LS-means (least squares means, also known as population means and as marginal means) for a range of model types.

Usage

LSmeans(object, effect = NULL, at = NULL, level = 0.95, ...)
# S3 method for default
LSmeans(object, effect = NULL, at = NULL, level = 0.95, ...)
# S3 method for lmerMod
LSmeans(object, effect = NULL, at = NULL, level = 0.95, adjust.df = TRUE, ...)
popMeans(object, effect = NULL, at = NULL, level = 0.95, ...)
# S3 method for default
popMeans(object, effect = NULL, at = NULL, level = 0.95, ...)
# S3 method for lmerMod
popMeans(object, effect = NULL, at = NULL, level = 0.95, adjust.df = TRUE, ...)

Value

A dataframe with results from computing the contrasts.

Arguments

object

Model object

effect

A vector of variables. For each configuration of these the estimate will be calculated.

at

A list of values of covariates (including levels of some factors) to be used in the calculations

level

The level of the (asymptotic) confidence interval.

...

Additional arguments; currently not used.

adjust.df

Should denominator degrees of freedom be adjusted?

Warning

Notice that LSmeans and LE_matrix fails if the model formula contains an offset (as one would have in connection with e.g. Poisson regression.

Author

Søren Højsgaard,

Details

There are restrictions on the formulas allowed in the model object. For example having y ~ log(x) will cause an error. Instead one must define the variable logx = log(x) and do y ~ logx.

See Also

LE_matrix, linest

Examples

## Two way anova:

data(warpbreaks)

m0 <- lm(breaks ~ wool + tension, data=warpbreaks)
m1 <- lm(breaks ~ wool * tension, data=warpbreaks)
LSmeans(m0)
LSmeans(m1)

## same as:
K <- LE_matrix(m0);K
linest(m0, K)
K <- LE_matrix(m1);K
linest(m1, K)

LE_matrix(m0, effect="wool")
LSmeans(m0, effect="wool")

LE_matrix(m1, effect="wool")
LSmeans(m1, effect="wool")

LE_matrix(m0, effect=c("wool", "tension"))
LSmeans(m0, effect=c("wool", "tension"))

LE_matrix(m1, effect=c("wool", "tension"))
LSmeans(m1, effect=c("wool", "tension"))


## Regression; two parallel regression lines:

data(Puromycin)

m0 <- lm(rate ~ state + log(conc), data=Puromycin)
## Can not use LSmeans / LE_matrix here because of
## the log-transformation. Instead we must do:
Puromycin$lconc <- log( Puromycin$conc )
m1 <- lm(rate ~ state + lconc, data=Puromycin)

LE_matrix(m1)
LSmeans(m1)

LE_matrix(m1, effect="state")
LSmeans(m1, effect="state")

LE_matrix(m1, effect="state", at=list(lconc=3))
LSmeans(m1, effect="state", at=list(lconc=3))

## Non estimable contrasts

## ## Make balanced dataset
dat.bal <- expand.grid(list(AA=factor(1:2), BB=factor(1:3),
                            CC=factor(1:3)))
dat.bal$y <- rnorm(nrow(dat.bal))

## ## Make unbalanced dataset
#      'BB' is nested within 'CC' so BB=1 is only found when CC=1
#       and BB=2,3 are found in each CC=2,3,4
dat.nst <- dat.bal
dat.nst$CC <-factor(c(1, 1, 2, 2, 2, 2, 1, 1, 3, 3,
                      3, 3, 1, 1, 4, 4, 4, 4))

mod.bal  <- lm(y ~ AA + BB * CC,    data=dat.bal)
mod.nst  <- lm(y ~ AA + BB : CC, data=dat.nst)

LSmeans(mod.bal, effect=c("BB", "CC"))
LSmeans(mod.nst, effect=c("BB", "CC"))
LSmeans(mod.nst, at=list(BB=1, CC=1))

LSmeans(mod.nst, at=list(BB=1, CC=2))
## Above: NA's are correct; not an estimable function

if( require( lme4 )){
 warp.mm <- lmer(breaks ~ -1 + tension + (1|wool), data=warpbreaks)
 LSmeans(warp.mm, effect="tension")
 class(warp.mm)
 fixef(warp.mm)
 coef(summary(warp.mm))
 vcov(warp.mm)
 if (require(pbkrtest))
   vcovAdj(warp.mm)
}

LSmeans(warp.mm, effect="tension")