fitdistrplus (version 1.1-6)

fluazinam: Species-Sensitivity Distribution (SSD) for Fluazinam

Description

48-hour acute toxicity values (EC50 values) for exposure of macroinvertebrates and zooplancton to fluazinam.

Usage

data(fluazinam)

Format

fluazinam is a data frame with 2 columns named left and right, describing each observed EC50 value (in micrograms per liter) as an interval. The left column contains either NA for left censored observations, the left bound of the interval for interval censored observations, or the observed value for non-censored observations. The right column contains either NA for right censored observations, the right bound of the interval for interval censored observations, or the observed value for noncensored observations.

Examples

# NOT RUN {
# (1) load of data
#
data(fluazinam)

# (2) plot of data using Turnbull cdf plot
#
log10EC50 <-log10(fluazinam)
plotdistcens(log10EC50)

# (3) fit of a lognormal and a logistic distribution to data
# (classical distributions used for species sensitivity 
# distributions, SSD, in ecotoxicology)
# and visual comparison of the fits using Turnbull cdf plot 
#
fln <- fitdistcens(log10EC50,"norm")
summary(fln)

fll <- fitdistcens(log10EC50,"logis")
summary(fll)

cdfcompcens(list(fln,fll),legendtext=c("normal","logistic"),
xlab = "log10(EC50)")

# (4) estimation of the 5 percent quantile value of 
# the normal fitted distribution (5 percent hazardous concentration  : HC5)
# with its two-sided 95 percent confidence interval calculated by 
# non parametric bootstrap
# with a small number of iterations to satisfy CRAN running times constraint.
# For practical applications, we recommend to use at least niter=501 or niter=1001.
#
# in log10(EC50)
bln <- bootdistcens(fln, niter=101)
HC5ln <- quantile(bln, probs = 0.05)
# in EC50
10^(HC5ln$quantiles)
10^(HC5ln$quantCI)

# (5) estimation of the HC5 value
# with its one-sided 95 percent confidence interval (type "greater")
#
# in log10(EC50)
HC5lnb <- quantile(bln,probs = 0.05,CI.type="greater")

# in LC50
10^(HC5lnb$quantiles)
10^(HC5lnb$quantCI)

# }