yip: Years in Period

Description

Given any starting and ending dates, it generates:
1) a vector of class Date with all the years between the two dates (both of them included), OR
2) the amount of years between the two dates

Usage

yip(from, to, date.fmt = "%Y-%m-%d", out.type = "seq")

Value

Depending on the value of out.type, it returns:

1) seq : a vector of class Date with all the years between from and to (both of them included), OR

2) nmbr: a single numeric value with the amount of years between the two dates.

Arguments

from: Character indicating the starting date for creating the sequence. It has to be in the format indicated by date.fmt.
to: Character indicating the ending date for creating the sequence. It has to be in the format indicated by date.fmt.
date.fmt: character indicating the format in which the dates are stored in from and to, e.g. %Y-%m-%d. See format in as.Date.
out.type: Character indicating the type of result that is given by this function. Valid values are:
-) seq => a vectorial sequence with all the years within the given dates.
-) nmbr => the number of years within the given dates.

Author

Mauricio Zambrano-Bigiarini, mzb.devel@gmail

Examples

Run this code

# Sequence of monthly dates between "1961-01-01" and "1961-12-31"
yip("1961-01-01", "1961-12-31")

## Computing the number of years between 1961 and 1975, 
## by using "%d-%m-%Y" as date format   ##
yip("01-01-1961", "01-01-1975", date.fmt= "%d-%m-%Y", out.type = "nmbr")