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kutils (version 1.73)

zapspace: Convert leading or trailing white space and tab characters to nothing.

Description

This eliminates any characters matched by the regular expression `\s` if they appear at the beginning of a string or at its end. It does not alter spaces in the interior of a string. This was created when I was not aware of R's trimws and the purpose is the same. On our TODO list, we intend to eliminate this function and replace its use with trimws

Usage

zapspace(x)

Value

If x is a character vector, return is a character vector with leading and trailing white space values removed. If x is not a character vector, an unaltered x is returned.

Arguments

x

A character vector

Author

Paul Johnson <pauljohn@ku.edu>

Examples

Run this code
x <-  c("", " ", "   ", "\t", "\t some", "some\t", " space first")
zapspace(x)

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