lifecontingencies (version 1.3.12)

Axn: Function to evaluate life insurance.

Description

This function evaluates n - years term and whole life insurance.

Usage

Axn(actuarialtable, x, n, i=actuarialtable@interest, 
	m, k=1, type = "EV", power=1, ...)

Value

A numeric value representing either the actuarial value of the coverage (when type="EV") or a number drawn from the underlying distribution of Axn.

Arguments

actuarialtable

An actuarial table object.

x

Age of the insured. (can be a vector).

n

Coverage period, if missing the insurance is considered whole life \(n=\omega-x-m\). (can be a vector).

i

Interest rate (overrides the interest rate slot in actuarialtable). (should be a scalar).

m

Deferring period, even fractional, if missing assumed to be 0. (can be a vector).

k

Number of periods per year at the end of which the capital is payable in case of insured event, default=1 (capital payable at the end of death year). (should be a scalar).

type

A string, either "EV" for expected value of the actuarial present value (default) or "ST" for one stochastic realization of the underlying present value of benefits. Alternatively, one can use "expected" or "stochastic" respectively (can be abbreviated).

power

The power of the APV. Default is 1 (mean)

...

Arguments to be passed to pxt().

Author

Giorgio A. Spedicato

Warning

The function is provided as is, without any guarantee regarding the accuracy of calculation. We disclaim any liability for eventual losses arising from direct or indirect use of this software.

Details

The variance calculation has not been implemented yet.

References

Actuarial Mathematics (Second Edition), 1997, by Bowers, N.L., Gerber, H.U., Hickman, J.C., Jones, D.A. and Nesbitt, C.J.

See Also

axn, Exn

Examples

	
		#assume SOA example life table to be load
		data(soaLt)
		soa08Act=with(soaLt, new("actuarialtable",interest=0.06,
		x=x,lx=Ix,name="SOA2008"))
		#evaluate the value of a 40 years term life insurance for an aged 25
		Axn(actuarialtable=soa08Act, x=25, n=40) 
		#check an relevant life contingencies relationship
		k=12
		i=0.06
		j=real2Nominal(i,k)
		Axn(soa08Act, 30,k=12)
		i/j*Axn(soa08Act, 30,k=1)