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lpSolveAPI (version 5.5.0.12-3)

set.row: Set Row

Description

Set a column in an lpSolve linear program model object.

Usage

set.row(lprec, row, xt, indices = 1:n)

Arguments

lprec
an lpSolve linear program model object.
row
a single numeric value from the set {1, ..., m} (where m is the number of constraints in lprec) specifying which column to set.
xt
a numeric vector containing the constraint coefficients (only the nonzero coefficients if indices is also given). The length of xt must be equal to the number of decision variables in lprec unless indices
indices
a numeric vector the same length as xt of unique values from the set {1, ..., n} (where n is the number of decision variables in lprec); xt[j] becomes the constraint coefficient for variable indices[j].

Value

  • a logical value indicating whether the row was successfully set.

References

http://lpsolve.sourceforge.net/5.5/index.htm

Examples

Run this code
lps.model <- make.lp(2, 4)

xt <- c(6,2,4,9)
set.row(lps.model, 2, xt)

yt <- c(3,1,5)
ind <- c(1,2,4)
set.row(lps.model, 1, yt, ind)

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