mizer (version 2.5.3)

getMeanMaxWeight: Calculate the mean maximum weight of the community

Description

Calculates the mean maximum weight of the community through time. This can be calculated by numbers or biomass. The calculation is the sum of the w_max * abundance of each species, divided by the total abundance community, where abundance is either in biomass or numbers. You can specify minimum and maximum weight or length range for the species. Lengths take precedence over weights (i.e. if both min_l and min_w are supplied, only min_l will be used). You can also specify the species to be used in the calculation.

Usage

getMeanMaxWeight(sim, species = NULL, measure = "both", ...)

Value

Depends on the measure argument. If measure = “both”

then you get a matrix with two columns, one with values by numbers, the other with values by biomass at each saved time step. If measure = “numbers” or “biomass” you get a vector of the respective values at each saved time step.

Arguments

sim

A MizerSim object

species

The species to be selected. Optional. By default all target species are selected. A vector of species names, or a numeric vector with the species indices, or a logical vector indicating for each species whether it is to be selected (TRUE) or not.

measure

The measure to return. Can be 'numbers', 'biomass' or 'both'

...

Arguments passed on to get_size_range_array

min_w

Smallest weight in size range. Defaults to smallest weight in the model.

max_w

Largest weight in size range. Defaults to largest weight in the model.

min_l

Smallest length in size range. If supplied, this takes precedence over min_w.

max_l

Largest length in size range. If supplied, this takes precedence over max_w.

See Also

Other functions for calculating indicators: getCommunitySlope(), getMeanWeight(), getProportionOfLargeFish()

Examples

mmw <- getMeanMaxWeight(NS_sim)
years <- c("1967", "2010")
mmw[years, ]
getMeanMaxWeight(NS_sim, species=c("Herring","Sprat","N.pout"))[years, ]
getMeanMaxWeight(NS_sim, min_w = 10, max_w = 5000)[years, ]