### Minimize the Hartmann6 function
hartmann6 <- function(x) {
a <- c(1.0, 1.2, 3.0, 3.2)
A <- matrix(c(10.0, 0.05, 3.0, 17.0,
3.0, 10.0, 3.5, 8.0,
17.0, 17.0, 1.7, 0.05,
3.5, 0.1, 10.0, 10.0,
1.7, 8.0, 17.0, 0.1,
8.0, 14.0, 8.0, 14.0), nrow=4, ncol=6)
B <- matrix(c(.1312,.2329,.2348,.4047,
.1696,.4135,.1451,.8828,
.5569,.8307,.3522,.8732,
.0124,.3736,.2883,.5743,
.8283,.1004,.3047,.1091,
.5886,.9991,.6650,.0381), nrow=4, ncol=6)
fun <- 0
for (i in 1:4) {
fun <- fun - a[i] * exp(-sum(A[i,] * (x - B[i,]) ^ 2))
}
fun
}
S <- directL(hartmann6, rep(0, 6), rep(1, 6),
nl.info = TRUE, control = list(xtol_rel = 1e-8, maxeval = 1000))
## Number of Iterations....: 1000
## Termination conditions: stopval: -Inf
## xtol_rel: 1e-08, maxeval: 1000, ftol_rel: 0, ftol_abs: 0
## Number of inequality constraints: 0
## Number of equality constraints: 0
## Current value of objective function: -3.32236800687327
## Current value of controls:
## 0.2016884 0.1500025 0.4768667 0.2753391 0.311648 0.6572931
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