data1 <- list(x = c(1,2,3,5,6,8,9,11,12,14,15),
y = c(rep(10,6), 10.5,15,50,60,95))
data2 <- list(x = c(0,1,4,6.5,9,10),
y = c(10,4,2,1,3,10))
data3 <- list(x = c(7.99,8.09,8.19,8.7,9.2,10,12,15,20),
y = c(0,0.000027629,0.00437498,0.169183,0.469428,
0.94374,0.998636,0.999919,0.999994))
data4 <- list(x = c(22,22.5,22.6,22.7,22.8,22.9,
23,23.1,23.2,23.3,23.4,23.5,24),
y = c(523,543,550,557,565,575,
590,620,860,915,944,958,986))
data5 <- list(x = c(0,1.1,1.31,2.5,3.9,4.4,5.5,6,8,10.1),
y = c(10.1,8,4.7,4.0,3.48,3.3,5.8,7,7.7,8.6))
data6 <- list(x = c(-0.8, -0.75, -0.3, 0.2, 0.5),
y = c(-0.9, 0.3, 0.4, 0.5, 0.6))
data7 <- list(x = c(-1, -0.96, -0.88, -0.62, 0.13, 1),
y = c(-1, -0.4, 0.3, 0.78, 0.91, 1))
data8 <- list(x = c(-1, -2/3, -1/3, 0.0, 1/3, 2/3, 1),
y = c(-1, -(2/3)^3, -(1/3)^3, -(1/3)^3, (1/3)^3, (1/3)^3, 1))
opr <- par(mfrow=c(2,2))
# These are well-known test cases:
D <- data1
plot(D, ylim=c(0, 100)); grid()
xp <- seq(1, 15, len=51); yp <- spinterp(D$x, D$y, xp)
lines(spline(D), col="blue")
lines(xp, yp, col="red")
D <- data3
plot(D, ylim=c(0, 1.2)); grid()
xp <- seq(8, 20, len=51); yp <- spinterp(D$x, D$y, xp)
lines(spline(D), col="blue")
lines(xp, yp, col="red")
D <- data4
plot(D); grid()
xp <- seq(22, 24, len=51); yp <- spinterp(D$x, D$y, xp)
lines(spline(D), col="blue")
lines(xp, yp, col="red")
# Fix a horizontal slope at the end points
D <- data8
x <- c(-1.05, D$x, 1.05); y <- c(-1, D$y, 1)
plot(D); grid()
xp <- seq(-1, 1, len=101); yp <- spinterp(x, y, xp)
lines(spline(D, n=101), col="blue")
lines(xp, yp, col="red")
par(opr)
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