Remove/replace/extract percentages from a string.
rm_percent(
text.var,
trim = !extract,
clean = TRUE,
pattern = "@rm_percent",
replacement = "",
extract = FALSE,
dictionary = getOption("regex.library"),
...
)ex_percent(
text.var,
trim = !extract,
clean = TRUE,
pattern = "@rm_percent",
replacement = "",
extract = TRUE,
dictionary = getOption("regex.library"),
...
)
Returns a character string with percentages removed.
The text variable.
logical. If TRUE
removes leading and trailing white
spaces.
trim logical. If TRUE
extra white spaces and escaped
character will be removed.
A character string containing a regular expression (or
character string for fixed = TRUE
) to be matched in the given
character vector. Default, @rm_percent
uses the
rm_percent
regex from the regular expression dictionary from
the dictionary
argument.
Replacement for matched pattern
.
logical. If TRUE
the percentages are extracted into a
list of vectors.
A dictionary of canned regular expressions to search within
if pattern
begins with "@rm_"
.
Other arguments passed to gsub
.
Other rm_ functions:
rm_abbreviation()
,
rm_between()
,
rm_bracket()
,
rm_caps_phrase()
,
rm_caps()
,
rm_citation_tex()
,
rm_citation()
,
rm_city_state_zip()
,
rm_city_state()
,
rm_date()
,
rm_default()
,
rm_dollar()
,
rm_email()
,
rm_emoticon()
,
rm_endmark()
,
rm_hash()
,
rm_nchar_words()
,
rm_non_ascii()
,
rm_non_words()
,
rm_number()
,
rm_phone()
,
rm_postal_code()
,
rm_repeated_characters()
,
rm_repeated_phrases()
,
rm_repeated_words()
,
rm_tag()
,
rm_time()
,
rm_title_name()
,
rm_url()
,
rm_white()
,
rm_zip()
x <- c("There is $5.50 for me.", "that's 45.6% of the pizza",
"14% is $26 or $25.99")
rm_percent(x)
ex_percent(x)
Run the code above in your browser using DataLab