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spacetime (version 1.3-2)

unstack: write STFDF to table forms

Description

create table forms of STFDF objects

Usage

# S3 method for STFDF
unstack(x, form, which = 1, ...)
# S3 method for STFDF
as.data.frame(x, row.names, ...)

Value

unstack returns the data in wide format, with each row representing a spatial entity and each column a time; see unstack for details and default behaviour.

as.data.frame returns the data.frame in long format, where the coordinates of the spatial locations (or line starting coordinates, or polygon center points) and time stamps are recycled accordingly.

Arguments

x

object of class STFDF

form

formula; can be omitted

which

column name or number to have unstacked

row.names

row.names for the data.frame returned

...

arguments passed on to the functions unstack or as.data.frame

Examples

Run this code
sp = cbind(x = c(0,0,1), y = c(0,1,1))
row.names(sp) = paste("point", 1:nrow(sp), sep="")
library(sp)
sp = SpatialPoints(sp)
library(xts)
time = xts(1:4, as.POSIXct("2010-08-05")+3600*(10:13))
m = c(10,20,30) # means for each of the 3 point locations
mydata = rnorm(length(sp)*length(time),mean=rep(m, 4))
IDs = paste("ID",1:length(mydata))
mydata = data.frame(values = signif(mydata,3), ID=IDs)
stfdf = STFDF(sp, time, mydata)
as.data.frame(stfdf, row.names = IDs)
unstack(stfdf)
t(unstack(stfdf))
unstack(stfdf, which = 2)

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