ARMAtoMA(ar = numeric(), ma = numeric(), lag.max)
arima
, ARMAacf
.ARMAtoMA(c(1.0, -0.25), 1.0, 10)
## Example from Brockwell & Davis (1991, p.92)
## answer (1 + 3*n)*2^(-n)
n <- 1:10; (1 + 3*n)*2^(-n)
Run the code above in your browser using DataLab