fruits <- c("one apple", "two pears", "three bananas")
str_replace(fruits, "[aeiou]", "-")
str_replace_all(fruits, "[aeiou]", "-")
str_replace_all(fruits, "[aeiou]", toupper)
str_replace_all(fruits, "b", NA_character_)
str_replace(fruits, "([aeiou])", "")
str_replace(fruits, "([aeiou])", "\\1\\1")
# Note that str_replace() is vectorised along text, pattern, and replacement
str_replace(fruits, "[aeiou]", c("1", "2", "3"))
str_replace(fruits, c("a", "e", "i"), "-")
# If you want to apply multiple patterns and replacements to the same
# string, pass a named vector to pattern.
fruits %>%
str_c(collapse = "---") %>%
str_replace_all(c("one" = "1", "two" = "2", "three" = "3"))
# Use a function for more sophisticated replacement. This example
# replaces colour names with their hex values.
colours <- str_c("\\b", colors(), "\\b", collapse="|")
col2hex <- function(col) {
rgb <- col2rgb(col)
rgb(rgb["red", ], rgb["green", ], rgb["blue", ], max = 255)
}
x <- c(
"Roses are red, violets are blue",
"My favourite colour is green"
)
str_replace_all(x, colours, col2hex)
Run the code above in your browser using DataLab